Optimal. Leaf size=283 \[ \frac{20 x+37}{217 \sqrt{2 x+1} \left (5 x^2+3 x+2\right )}-\frac{604}{1519 \sqrt{2 x+1}}-\frac{\sqrt{\frac{1}{434} \left (5682718+968975 \sqrt{35}\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{1519}+\frac{\sqrt{\frac{1}{434} \left (5682718+968975 \sqrt{35}\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{1519}+\frac{\sqrt{\frac{2}{217} \left (968975 \sqrt{35}-5682718\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{1519}-\frac{\sqrt{\frac{2}{217} \left (968975 \sqrt{35}-5682718\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{1519} \]
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Rubi [A] time = 1.18793, antiderivative size = 283, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364 \[ \frac{20 x+37}{217 \sqrt{2 x+1} \left (5 x^2+3 x+2\right )}-\frac{604}{1519 \sqrt{2 x+1}}-\frac{\sqrt{\frac{1}{434} \left (5682718+968975 \sqrt{35}\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{1519}+\frac{\sqrt{\frac{1}{434} \left (5682718+968975 \sqrt{35}\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{1519}+\frac{\sqrt{\frac{2}{217} \left (968975 \sqrt{35}-5682718\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{1519}-\frac{\sqrt{\frac{2}{217} \left (968975 \sqrt{35}-5682718\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{1519} \]
Antiderivative was successfully verified.
[In] Int[1/((1 + 2*x)^(3/2)*(2 + 3*x + 5*x^2)^2),x]
[Out]
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Rubi in Sympy [A] time = 77.6577, size = 386, normalized size = 1.36 \[ - \frac{\sqrt{14} \left (814 + 151 \sqrt{35}\right ) \log{\left (2 x - \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{21266 \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{14} \left (814 + 151 \sqrt{35}\right ) \log{\left (2 x + \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{21266 \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{35} \left (- \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \left (1628 + 302 \sqrt{35}\right )}{10} + \frac{1628 \sqrt{10} \sqrt{2 + \sqrt{35}}}{5}\right ) \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} - \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{10633 \sqrt{-2 + \sqrt{35}} \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{35} \left (- \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \left (1628 + 302 \sqrt{35}\right )}{10} + \frac{1628 \sqrt{10} \sqrt{2 + \sqrt{35}}}{5}\right ) \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} + \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{10633 \sqrt{-2 + \sqrt{35}} \sqrt{2 + \sqrt{35}}} + \frac{20 x + 37}{217 \sqrt{2 x + 1} \left (5 x^{2} + 3 x + 2\right )} - \frac{604}{1519 \sqrt{2 x + 1}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(1+2*x)**(3/2)/(5*x**2+3*x+2)**2,x)
[Out]
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Mathematica [C] time = 1.06107, size = 160, normalized size = 0.57 \[ \frac{2 \left (-\frac{31 \left (3020 x^2+1672 x+949\right )}{2 \sqrt{2 x+1} \left (5 x^2+3 x+2\right )}-\frac{i \left (512 \sqrt{31}-4681 i\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2-i \sqrt{31}}}\right )}{\sqrt{-\frac{1}{5} i \left (\sqrt{31}-2 i\right )}}+\frac{i \left (512 \sqrt{31}+4681 i\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2+i \sqrt{31}}}\right )}{\sqrt{\frac{1}{5} i \left (\sqrt{31}+2 i\right )}}\right )}{47089} \]
Antiderivative was successfully verified.
[In] Integrate[1/((1 + 2*x)^(3/2)*(2 + 3*x + 5*x^2)^2),x]
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Maple [B] time = 0.043, size = 494, normalized size = 1.8 \[ -{\frac{16}{49}{\frac{1}{\sqrt{1+2\,x}}}}-{\frac{16}{49} \left ({\frac{27}{124} \left ( 1+2\,x \right ) ^{{\frac{3}{2}}}}-{\frac{89}{310}\sqrt{1+2\,x}} \right ) \left ( \left ( 1+2\,x \right ) ^{2}-{\frac{8\,x}{5}}+{\frac{3}{5}} \right ) ^{-1}}-{\frac{3657\,\sqrt{20+10\,\sqrt{35}}\sqrt{35}}{3296230}\ln \left ( 5+10\,x+\sqrt{35}-\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }-{\frac{256\,\sqrt{20+10\,\sqrt{35}}}{47089}\ln \left ( 5+10\,x+\sqrt{35}-\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }-{\frac{ \left ( 73140+36570\,\sqrt{35} \right ) \sqrt{35}}{1648115\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }-{\frac{10240+5120\,\sqrt{35}}{47089\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }+{\frac{3256\,\sqrt{35}}{10633\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }+{\frac{3657\,\sqrt{20+10\,\sqrt{35}}\sqrt{35}}{3296230}\ln \left ( 5+10\,x+\sqrt{35}+\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }+{\frac{256\,\sqrt{20+10\,\sqrt{35}}}{47089}\ln \left ( 5+10\,x+\sqrt{35}+\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }-{\frac{ \left ( 73140+36570\,\sqrt{35} \right ) \sqrt{35}}{1648115\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }-{\frac{10240+5120\,\sqrt{35}}{47089\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }+{\frac{3256\,\sqrt{35}}{10633\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(1+2*x)^(3/2)/(5*x^2+3*x+2)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}{\left (2 \, x + 1\right )}^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((5*x^2 + 3*x + 2)^2*(2*x + 1)^(3/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.28272, size = 1351, normalized size = 4.77 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((5*x^2 + 3*x + 2)^2*(2*x + 1)^(3/2)),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\left (2 x + 1\right )^{\frac{3}{2}} \left (5 x^{2} + 3 x + 2\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(1+2*x)**(3/2)/(5*x**2+3*x+2)**2,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}{\left (2 \, x + 1\right )}^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((5*x^2 + 3*x + 2)^2*(2*x + 1)^(3/2)),x, algorithm="giac")
[Out]